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0.36=0.5(x^2)
We move all terms to the left:
0.36-(0.5(x^2))=0
We get rid of parentheses
-0.5x^2+0.36=0
a = -0.5; b = 0; c = +0.36;
Δ = b2-4ac
Δ = 02-4·(-0.5)·0.36
Δ = 0.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.72}}{2*-0.5}=\frac{0-\sqrt{0.72}}{-1} =-\frac{\sqrt{}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.72}}{2*-0.5}=\frac{0+\sqrt{0.72}}{-1} =\frac{\sqrt{}}{-1} $
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